解:当追上时有V0T=1/2 aT2得T=15S当他们距离最大时,就是摩托和汽和租喊车速度相同唤野的时候:即V0=aT1得T1=7.5S则型侍Smax=V0T1-1/2 a T1 2 =56.25m
设t时追埋核上则 15t+100=1/2×2×t^2t=20s追上卜岁前速度相等时距离最大即15=2t’t'弯弊掘=7.5s此时ΔS=15×7.5+100—1/2×2×7.5^2=156.25m