解:∵OM平分∠BOC,ON平分∠AOC
∴掘指∠MOC=1/2∠BOC
∠NOC=1/2∠AOC
∴∠MON=∠判斗配MOC+∠NOC
=1/2∠BOC+1/2∠AOC
=1/2(∠BOC+∠AOC)
=1/2∠销铅AOB
=1/2x97°
=48.5°
48.5
48.5°
解:因为OM平分∠BOC,ON平分∠配闭AOC
所以∠MOC=1/2∠BOC
∠NOC=1/2∠AOC
所以由此可知∠MON=∠信凳MOC+∠NOC
=1/2∠培坦裂BOC+1/2∠AOC
=1/2(∠BOC+∠AOC)
=1/2∠AOB
=1/2x97°
=48.5°